From a uniform solid cone of base radius $R$ and height $H$ , a symmetric cone of the base radius $\frac{R}{2}$ is removed as shown. Then the centre of mass is shifted by $\frac{H}{n} .$ Find the value of $n$ .

Question

From a uniform solid cone of base radius R and height H, a symmetric cone of the base radius R/2 is removed as shown. Then the centre of mass is shifted by H/n. Find the value of n.

MARKS Content Team · Accepted Answer

Correct answer: 56. y_COM=(m_1y_1-m_2y_2)/(m_1-m_2) =M.H/4-M/8H/8M-M/8 =15H/56 Δy=15H/56-H/4 =H/56

From a uniform solid cone of base radius $R$ and height $H$ , a symmetric cone of the base radius $\frac{R}{2}$ is removed as shown. Then the centre of mass is shifted by $\frac{H}{n} .$ Find the value of $n$ .

Solution

More Center of Mass Momentum and Collision Questions

From a uniform solid cone of base radius R and height H, a symmetric cone of the base radius R2 is removed as shown. Then the centre of mass is shifted by Hn. Find the value of n.

Solution

More Center of Mass Momentum and Collision Questions

From a uniform solid cone of base radius $R$ and height $H$ , a symmetric cone of the base radius $\frac{R}{2}$ is removed as shown. Then the centre of mass is shifted by $\frac{H}{n} .$ Find the value of $n$ .