Q160 / 225 · JEE Main 2002 · Physics
Tube A has both ends open while tube B has one end closed, otherwise they are identical. The ratio of fundamental frequency of tube $A$ and $B$ is
- A1 : 2
- B1 : 4
- Correct answerC2 : 1
- D4 : 1
Solution
$\frac{\lambda_{\mathrm{A}}}{\lambda_{\mathrm{B}}}=\frac{1}{2} \Rightarrow \frac{\mathrm{n}_{\mathrm{A}}}{\mathrm{n}_{\mathrm{B}}}=\frac{2}{1}$




Hence, the correct answer is option: 'C'.