Q160 / 225 · JEE Main 2002 · Physics

Tube A has both ends open while tube B has one end closed, otherwise they are identical. The ratio of fundamental frequency of tube $A$ and $B$ is

  • A
    1 : 2
  • B
    1 : 4
  • Correct answer
    C
    2 : 1
  • D
    4 : 1

Solution

$\frac{\lambda_{\mathrm{A}}}{\lambda_{\mathrm{B}}}=\frac{1}{2} \Rightarrow \frac{\mathrm{n}_{\mathrm{A}}}{\mathrm{n}_{\mathrm{B}}}=\frac{2}{1}$ Figure
Figure

Hence, the correct answer is option: 'C'.

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