Total number of elements which are present in a row on the periodic table between those elements, whose wavelength of K_(α) lines are equal to 250 and…

Question

Total number of elements which are present in a row on the periodic table between those elements, whose wavelength of K_(α) lines are equal to 250 and 179 pm are (Rydberg constant = 1.097 × 10^7 m^(-1))

MARKS Content Team · Accepted Answer

Correct answer: 3. Wavelength of K_(α) line is given by λ=4/(3RZ-1^2) For λ, between 250 and 179 pm three elements are possible ( Z = 24, 25 and 26 ).

Total number of elements which are present in a row on the periodic table between those elements, whose wavelength of $K_{α}$ lines are equal to $250$ and $179 pm$ are (Rydberg constant = $1.097 \times 10^{7} m^{- 1}$ )

Solution

More Atomic Physics Questions

Total number of elements which are present in a row on the periodic table between those elements, whose wavelength of Kα lines are equal to 250 and 179 pm are (Rydberg constant = 1.097 × 107 m-1)

Solution

More Atomic Physics Questions

Total number of elements which are present in a row on the periodic table between those elements, whose wavelength of $K_{α}$ lines are equal to $250$ and $179 pm$ are (Rydberg constant = $1.097 \times 10^{7} m^{- 1}$ )