Q20 / 104 · NTA Abhyas (JEE Main) 2020 · Physics · Atomic Physics

The angular momentum of an electron in Bohr's hydrogen atom whose energy is - 3.4 eV, is

A
$\frac{5 h}{2 π}$
B
$\frac{h}{2 π}$
Correct answer
C
$\frac{h}{π}$
D
$\frac{2 h}{3 π}$

Solution

The energy of an electron in nth orbit of a hydrogen atom is given by

E_{n} = - \frac{13.6}{n^{2}} eV

\Rightarrow 3.4 = - \frac{13.6}{n^{2}}

\Rightarrow n^{2} = 4

\Rightarrow n = 2

The angular momentum of electron is given by

L = \frac{n h}{2 π} = \frac{2 h}{2 π} = \frac{h}{π}

Hence, the correct answer is option: 'C'.

More Atomic Physics Questions

In a hydrogen-like species, the net force acting on a revolving electron in an orbit as given by the Bohr model is proportional to [ n → pri
Find the closest integer wavelength value of K α line (in picometer) in copper (Z = 29) if the wavelength of K α = line in iron (Z = 26) is
Wavelengths belonging to Balmer series lying in the range of 450 nm to 750 nm were used to eject photoelectrons from a metal surface whose w
The K α line obtained for molybdenum ( Z = 42 ) is 0.71 A ∘ . Then, the wavelength of the K α line of copper ( Z = 29 ) is
If the first excitation energy of a hydrogen-like atom is 27 . 3 eV , then the ionization energy of this atom will be
According to Bohr's model, the minimum energy (in eV ) required to remove an electron from the ground state of a doubly ionized Li atom Z =