Q31 / 180 · KCET 2010 · Chemistry
Time required for 100 per cent completion of a zero order reaction is
- A$\frac{2 k}{a}$
- B$\frac{\mathrm{a}}{2 \mathrm{k}}$
- Correct answerC$\frac{\mathrm{a}}{\mathrm{k}}$
- Dak
Solution
For zero order reactions,
$$
[\mathrm{A}]=-\mathrm{kt}+[\mathrm{A}]_{0}
$$
where, $[\mathrm{A}]_{0}=$ initial concentration $=\mathrm{a}$
$[\mathrm{A}]=$ remaining concentration $=\mathrm{a}-\mathrm{a}=0$
On putting values of $[\mathrm{A}]_{0}$ and $[\mathrm{A}]$, we get
$$
\mathrm{t}=\frac{\mathrm{a}}{\mathrm{k}}
$$
Hence, the correct answer is option: 'C'.