Q142 / 155 · WBJEE 2025 · Physics
Three different liquids are filled in a U-tube as shown in figure. Their densities are $\rho_1, \rho_2$ and $\rho_3$ respectively. From the figure we may conclude that


- A$\rho_3=4\left(\rho_2-\rho_1\right)$
- B$\rho_3=4\left(\rho_1-\rho_2\right)$
- Correct answerC$\rho_3=2\left(\rho_2-\rho_1\right)$
- D$\quad \rho_3=\frac{\rho_1+\rho_2}{2}$
Solution
$h \rho_1+\frac{h}{2} \rho_3=h \rho_2, \rho_1+\frac{\rho_3}{2}=\rho_2 \quad \quad \rho_3=2\left(\rho_2-\rho_1\right)$
Hence, the correct answer is option: 'C'.