Q30 / 181 · NTA Abhyas (JEE Main) 2020 · Physics · Laws of Motion

Three blocks are arranged on a horizontal table ABCD as shown in the figure. The strings and pulleys are massless and both the pulleys stand vertical. The strings connecting blocks m1 and m2 are also vertical and are perpendicular to faces AB and BC which are mutually perpendicular to each other. If m1 and m2 are 3 kg and 4 kg respectively. Coefficient of friction between the block m3=10 kg  and the surface is μ=0.6 then, frictional force on m3 is


Figure

  • A
    30 N
  • B
    40 N
  • Correct answer
    C
    50 N
  • D
    60 N

Solution

Net force on m3=302+402=50 N

And limiting friction on m3=μm3g=60 N

∴ System remain in equilibrium and friction on m3=50 N

Hence, the correct answer is option: 'C'.

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