Q11 / 181 · NTA Abhyas (JEE Main) 2020 · Physics · Laws of Motion

Three blocks A, B and C of equal mass m are placed one over the other on a smooth horizontal ground as shown in the figure. Coefficient of friction between any two blocks is 0.5. The maximum value of the mass of block D so that the blocks A, B and C move without slipping over each other is

Figure

  • A
    6 m
  • B
    5 m
  • Correct answer
    C
    3 m
  • D
    4 m

Solution

Blocks A and C both move due to friction. But less friction is available to A as compared to C because the normal reaction between A and B is less. Maximum friction between A and B can be

fmax=μ mAg=12mg

∴ Maximum acceleration of A can be

amax=fmaxm=g2

Further amax=mDg3m+mD

Or g2=mDg3m+mD

Or mD=3m

Hence, the correct answer is option: 'C'.

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