There are 4 oranges, 5 apples, 7 mangoes in a fruit basket. The number of ways of selecting at least one fruit from among the fruits in the basket is

Considering fruit of same kind to be identical. Now, if there are $p$ identical things of $1^{\text {st }}$ kind, $q$ identical of $2^{\text {nd }}$ kind and $r$ identical of $3^{\text {rd }}$ kind then total number of ways of selecting any number of objects are $(\mathrm{p}+1)(\mathrm{q}+1)(\mathrm{r}+1)$ in above given case Total number of ways $=(4+1)(5+1)(7+1)=240$ But there is one case in which 0 oranges, 0 apples and 0 mangoes are selected total no. of ways of selecting atleast one fruit $=240-1=239$.