Q42 / 214 · NTA Abhyas (NEET) 2020 · Physics · Oscillations

The x-t graph of a particle undergoing simple harmonic motion is shown below. The acceleration of the particle at t=23s is


Figure

  • A
    332π2cms2 
  • Correct answer
    B
    -π232cms2
  • C
    π232cms2
  • D
    - 332 π2cms2

Solution

Using the general equation of SHM

x=Asin⁡ωt

 as per graph A = 1 cm, T = 8 sec

⇒w= 2π T = π 4 x=sin π 4 t acceleration  a= d 2 x d t 2 ⇒a= − π 2 16 sin π 4 t at  t= 2 3 , a= − π 2 16 sin( π 4 . 2 3 )= − π 2 16 .sin( π 6 ) ⇒a= − π 2 16 × 1 2 = − π 2 32 cm/ s 2

Hence, the correct answer is option: 'B'.

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