A particle moves according to the law, =rcos(πt)/2. The distance covered by it during the time interval between t= 0 to t=3s is

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MARKS Content Team · Accepted Answer

Correct answer: (C) 3r. When t=0, x=rcos⁡(π×0)/2=r; When t=3s, x=rcos⁡(π×3)/2=0 Here ω=(π)/2 or (2π)/T=(π)/2 or T=4s ∴ In 3 sec, the particle goes from one extreme to other extreme and then back to mean position. So the distance travelled =2r+r=3r

A particle moves according to the law, $= r c o s \frac{π t}{2.}$ The distance covered by it during the time interval between t= 0 to t=3s is

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A particle moves according to the law, =rcosπt2. The distance covered by it during the time interval between t= 0 to t=3s is

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More Oscillations Questions

A particle moves according to the law, $= r c o s \frac{π t}{2.}$ The distance covered by it during the time interval between t= 0 to t=3s is