The work done in placing a charge of 8 × 10^-18 coulomb on a condenser of capacity 100 microfarad is

Correct answer: (C) 32 × 10^-32 joule. Work done =1/2 (q^2)/C=frac (8 × 10^-18 )^22 × 100 × 10^-6 =32 × 10^-32 ~J

Q77 / 100 · BITSAT 2023 (Memory Based Paper 1) · Physics

The work done in placing a charge of $8 \times 10^{-18}$ coulomb on a condenser of capacity 100 microfarad is

A
$3.1 \times 10^{-26}$ joule
B
$4 \times 10^{-10}$ joule
Correct answer
C
$32 \times 10^{-32}$ joule
D
$16 \times 10^{-32}$ joule

Solution

Work done $=\frac{1}{2} \frac{\mathrm{q}^2}{\mathrm{C}}=\frac{\left(8 \times 10^{-18}\right)^2}{2 \times 100 \times 10^{-6}}$
$=32 \times 10^{-32} \mathrm{~J}$

Hence, the correct answer is option: 'C'.

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