In a given network the equivalent capacitance between $A$ and $B$ is $C_{1}=C_{4}=1 \mu F, C_{2}=C_{3}=2 \mu F$.

• Correct answer
  A

  $3 \mu \mathrm{F}$
• B

  $6 \mu \mathrm{F}$
• C

  $4.5 \mu \mathrm{F}$
• D

  $2.5 \mu \mathrm{F}$

Solution

The equivalent circuit is shown in figure.
$\mathrm{C}_{\mathrm{AB}}=1+\frac{2 \times 2}{2+2}+1$ $\mathrm{C}_{\mathrm{AB}}=3 \mu \mathrm{F}$

Hence, the correct answer is option: 'A'.