Q145 / 160 · TS EAMCET 2023 (14 May Shift 1) · Physics
The Wheatstone bridge shown in the diagram is balanced. If $\mathrm{P}_3$ is the power dissipated by $\mathrm{R}_3$ and $\mathrm{P}_1$ is the power dissipated by $R_1$, then the ratio $\frac{\mathrm{P}_3}{\mathrm{P}_1}$ is


- Correct answerA$\frac{\mathrm{K}}{\mathrm{L}}$
- B$\frac{\mathrm{K}^2}{\mathrm{~L}}$
- C$\frac{\mathrm{L}}{\mathrm{K}^2}$
- D$\frac{\mathrm{L}}{\mathrm{K}}$
Solution
From wheat stone bridge, we have
$\begin{aligned} & \frac{R_1}{R_3}=\frac{L}{K} \\ & P=I^2 R \\ & \frac{P_3}{P_1}=\frac{I^2 R_3}{I^2 R_1}=\frac{K}{L}\end{aligned}$
Hence, the correct answer is option: 'A'.