The wavelength of electrons accelerated from rest through a potential difference of 40kV is X×10^(-12) m. The value of x is. (Nearest integer) Given…

Question

The wavelength of electrons accelerated from rest through a potential difference of $40 kV$ is $X \times 10^{- 12} m .$ The value of $x$ is. (Nearest integer)

Given: Mass of electron $= 9.1 \times 10^{- 31} kg$

Charge on an electron $= 1.6 \times 10^{- 19} C$

Planck's constant $= 6.63 \times 10^{- 34} Js$

MARKS Content Team · Accepted Answer

Correct answer: 6. De-broglie-wave length of electron: λ_e=h√(2 m(KE)) ∵e^(-)is accelerated from rest ⇒KE=q×V λ=h√2mqv =(6.63×10^(-34)√(2×1.6×10^(-19)×9.1×10^(-31)×40×10^3)=0.614×10^(-11) m=6.14×10^(-12) mNearest integer =6ORλ=12.3√VÅ=12.3)/200=6.15×10^(-12) m Ans. is 6

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The wavelength of electrons accelerated from rest through a potential difference of 40kV is X×10-12 m. The value of x is. (Nearest integer)Given: Mass of electron =9.1×10-31 kgCharge on an electron =1.6×10-19CPlanck's constant =6.63×10-34Js

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