Q75 / 75 · JEE Main 2025 (28 Jan Shift 2) · Physics
The volume contraction of a solid copper cube of edge length 10 cm , when subjected to a hydraulic pressure of $7 \times 10^6 \mathrm{~Pa}$, would be ____ $\mathrm{mm}^3$.
(Given bulk modulus of copper $=1.4 \times 10^{11} \mathrm{~N} \mathrm{~m}^{-2}$ )
Correct answer: 50
Solution
$\begin{aligned} & \mathrm{B}=\frac{\Delta \mathrm{P}}{\frac{\Delta \mathrm{V}}{\mathrm{V}}} \\ & \Delta \mathrm{V}=\frac{7 \times 10^6}{1.4 \times 10^{11}} \times\left(10 \times 10^{-2}\right)^3 \\ & \Delta \mathrm{~V}=50 \mathrm{~mm}^3\end{aligned}$
Hence, the correct answer is 50.