If average depth of an ocean is 4000 m and the bulk modulus of water is 2×10^9 N m^(-2), then fractional compression (ΔV)/V of water at the bottom of…

Question

If average depth of an ocean is 4000 m and the bulk modulus of water is 2×10^9 N m^(-2), then fractional compression (ΔV)/V of water at the bottom of ocean is α×10^(-2). The value of α is _______, (Given, g=10 m s^(-2), ρ=1000 kg m^(-3))

MARKS Content Team · Accepted Answer

Correct answer: 2. The formula to calculate the Bulk modulus is given by B=-(∆P)/(∆VV) ...1 From equation (1), the fractional compression in volume may be obtained as follows: -(ΔV)/V = (∆P)/B = (ρg∆h)/B ...2 From equation (2) it follows that -(∆V)/V = (1000×10×4000)/(2×10^9) ⇒ (∆V)/V=2×10^(-2) Hence, α=2.

If average depth of an ocean is $4000 m$ and the bulk modulus of water is $2 \times 10^{9} N m^{- 2}$ , then fractional compression $\frac{Δ V}{V}$ of water at the bottom of ocean is $α \times 10^{- 2}$ . The value of $α$ is _______, (Given, $g = 10 m s^{- 2}, ρ = 1000 kg m^{- 3}$ )

Solution

Relevant Questions

If average depth of an ocean is 4000 m and the bulk modulus of water is 2×109 N m-2, then fractional compression ΔVV of water at the bottom of ocean is α×10-2. The value of α is _______, (Given, g=10 m s-2, ρ=1000 kg m-3)

Solution

Relevant Questions

If average depth of an ocean is $4000 m$ and the bulk modulus of water is $2 \times 10^{9} N m^{- 2}$ , then fractional compression $\frac{Δ V}{V}$ of water at the bottom of ocean is $α \times 10^{- 2}$ . The value of $α$ is _______, (Given, $g = 10 m s^{- 2}, ρ = 1000 kg m^{- 3}$ )