Q59 / 75 · JEE Main 2020 (05 Sep Shift 2) · Physics

The velocity $(v)$ and time $(t)$ graph of a body in a straight line motion is shown in the figure. The point $S$ is at $4.333$ seconds. The total distance covered by the body in $6 s$ is :

Correct answer
A
$\frac{37}{3} m$
B
$12 m$
C
$11 m$
D
$\frac{49}{4} m$

Solution

Total distance covered by the body is equal to the modulus of area under graph velocity-time graph

$\Rightarrow d = (\frac{1}{2} \times 4 \times 2) + (4 \times 1) + (\frac{1}{2} \times 4 \times \frac{4}{3}) + (\frac{1}{2} \times 2 \times \frac{5}{3})$

$\Rightarrow d = 4 + 4 + \frac{8}{3} + \frac{5}{3}$

$\Rightarrow d = \frac{37}{3} m$

Hence, the correct answer is option: 'A'.

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The velocity (v) and time (t) graph of a body in a straight line motion is shown in the figure. The point S is at 4.333 seconds. The total distance covered by the body in 6 s is :

Solution

Relevant Questions

The velocity $(v)$ and time $(t)$ graph of a body in a straight line motion is shown in the figure. The point $S$ is at $4.333$ seconds. The total distance covered by the body in $6 s$ is :