Q68 / 75 · JEE Main 2025 (23 Jan Shift 1) · Physics

The motion of an airplane is represented by velocity-time graph as shown below. The distance covered by airplane in the first 30.5 second is _______ km . Figure

  • Correct answer
    A
    $12$
  • B
    $3$
  • C
    $6$
  • D
    $9$

Solution

Distance = area under the graph $\begin{aligned} d & =300 \times 2+400 \times 28.5 \\ & =600+114000 \\ & =12000 \mathrm{~m} \end{aligned}$

Hence, the correct answer is option: 'A'.

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