Q8 / 93 · NTA Abhyas (JEE Main) 2020 · Mathematics · Continuity and Differentiability

The value of f0, such that fx=1x21-cossinx can be made continuous at x=0, is 

  • Correct answer
    A
    12
  • B
    2
  • C
    14
  • D
    4

Solution

limx→0⁡1-cossinxx2=limx→0⁡2sin2⁡sinx2x2 limx→02.sinsinx2sinx22.sinx2x2=12⁡ 

Thus, for continuity at x=0,

f(0)=12

Hence, the correct answer is option: 'A'.

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