Q3 / 93 · NTA Abhyas (JEE Main) 2020 · Mathematics · Continuity and Differentiability

Let fx=min⁡4-x2,1+x2 ∀x∈-2,2, then the number of points where fx is non-differentiable is

  • A
    1
  • B
    0
  • Correct answer
    C
    4
  • D
    2

Solution

Clearly, from the graph we can see that fx is non-differentiable at 4 points

Figure

Hence, the correct answer is option: 'C'.

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