Q56 / 100 · BITSAT 2024 (Memory Based Paper 3) · Mathematics

The value of definite integral $\int_0^{\pi / 2} \log (\tan x) d x$ is

  • Correct answer
    A
    0
  • B
    $\frac{\pi}{4}$
  • C
    $\frac{\pi}{2}$
  • D
    $\pi$

Solution

Let $I=\int_0^{\frac{\pi}{2}} \log (\tan x) d x$....(i) By applying property, $\begin{aligned} \int_a^b f(x) d x & =\int_a^b f(a+b-x) d x \\ I & =\int_0^{\frac{\pi}{2}} \log \left(\tan \left(\frac{\pi}{2}-x\right)\right) d x \\ I & =\int_0^{\frac{\pi}{2}} \log (\cot x) d x\ldots(ii) \end{aligned}$ Adding Eqs. (i) and (ii), $\begin{aligned} & 2 I=\int_0^{\frac{\pi}{2}}[\log (\tan x)+\log (\cot x)] d x \\ & 2 I=\int_0^{\frac{\pi}{2}} \log 1 d x=0 \end{aligned}$

Hence, the correct answer is option: 'A'.

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