Q72 / 125 · BITSAT 2014 · Mathematics
$\int_{0}^{10} \frac{x^{10}}{(10-x)^{10}+x^{10}} d x$ is equal to
- A10
- Correct answerB5
- C2
- D$\frac{1}{0}$
Solution
Let $I=\int_{0}^{10} \frac{x^{10}}{(10-x)^{10}+x^{10}} d x$...(1)
$I=\int_{0}^{10} \frac{(10-x)^{10}}{(10-x)^{10}+x^{10}} d x$...(2)
Adding
(1) and (2), we get
$2 I=\int_{0}^{10} d x \Rightarrow 2 I=10 \Rightarrow I=5$
Hence, the correct answer is option: 'B'.