Q49 / 90 · JEE Main 2021 (25 Feb Shift 2) · Mathematics

The value of ∫-223x2-3x-6dx is

Correct answer: 19

Solution

∫-223x2-x-2dx

=3∫-22x2-x-2dx

=3∫-2-1x2-x-2dx+∫-12-x2-x-2dx

=3x33-x22-2x-2-1-x33-x22-2x-12

=37-23

=19

Hence, the correct answer is 19.

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