Q137 / 180 · KCET 2023 · Physics
The truth table for the given circuit is
- A
- B
- Correct answerC
- D
Solution
The given logic circuit diagram is
Output of the logic gate is $\begin{aligned} & Y=\overline{(\overline{A+B} \cdot(A B))}=\overline{A+B}+\overline{A B} \\ & \\ &=A+B+\bar{A}+\bar{B} \\ &=(A+\bar{A})+(B+\bar{B}) \\ &=1+1=1 .\end{aligned}$ Thus output is always 1 for all value of inputs $A$ and $B$. Hence, option (c) is correct.
Output of the logic gate is $\begin{aligned} & Y=\overline{(\overline{A+B} \cdot(A B))}=\overline{A+B}+\overline{A B} \\ & \\ &=A+B+\bar{A}+\bar{B} \\ &=(A+\bar{A})+(B+\bar{B}) \\ &=1+1=1 .\end{aligned}$ Thus output is always 1 for all value of inputs $A$ and $B$. Hence, option (c) is correct.
Hence, the correct answer is option: 'C'.