Q152 / 180 · KCET 2018 · Physics
If \( A=1 \) and \( B=0 \), then in terms of Boolean algebra, \( \bar{A}+B= \)
- Correct answerA\( B \)
- B\( \bar{B} \)
- C\( A \)
- D\( \bar{A} \)
Solution
\( A=1, B=0 \)
\( \bar{A}+B=1+0=0+0=0 \)
\( \bar{A}+B=B \)
Hence, the correct answer is option: 'A'.