Q61 / 90 · JEE Main 2011 · Physics

The transverse displacement $y(x, t)$ of a wave on a string is given by $y(x, t)=e^{-\left(a x^2+b t^2+2 \sqrt{a b} x t\right)}$. This represents a

  • Correct answer
    A
    wave moving in $-x$ direction with speed $\sqrt{\frac{b}{a}}$
  • B
    standing wave of frequency $\sqrt{b}$
  • C
    standing wave of frequency $\frac{1}{\sqrt{b}}$
  • D
    wave moving in $+x$ direction with $\sqrt{\frac{a}{b}}$

Solution

$$ y_{(x, t)}=e^{-}(\sqrt{a} x+\sqrt{b} t)^2 v=\sqrt{\frac{b}{a}} $$ Wave moving in - ve $\mathrm{x}$-direction.

Hence, the correct answer is option: 'A'.

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