Q81 / 90 · JEE Main 2023 (10 Apr Shift 1) · Physics

A transverse harmonic wave on a string is given by $y (x, t) = 5 \sin (6 t + 0.003 x)$ where $x$ and $y$ are in $cm$ and $t$ in $\sec$ . The wave velocity is _________ $m s^{- 1}$ .

Correct answer: 20

Solution

The general equation for a wave can be written as $y = A \sin (ω t + k x)$ . Comparing it with the given equation, $y = 5 \sin (6 t + 0.003 x)$ ,
$ω = 6 rad s^{- 1}$ , $k = 0.003 {cm}^{- 1}$
Using the equation, $v = \frac{ω}{k}$
$v = \frac{6}{0.003 \times 10^{2}} = 20 m s^{- 1}$

Hence, the correct answer is 20.

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A transverse harmonic wave on a string is given by yx, t=5 sin6t+0.003x where x and y are in cm and t in sec. The wave velocity is _________ m s-1.

Solution

Relevant Questions

A transverse harmonic wave on a string is given by $y (x, t) = 5 \sin (6 t + 0.003 x)$ where $x$ and $y$ are in $cm$ and $t$ in $\sec$ . The wave velocity is _________ $m s^{- 1}$ .