The transformation occurring in Duma's method is given below C_2H_7 N+2x+y/2CuO→xCO_2+y/2H_2O+z/2 N_2+2x+y/2Cu The value of y is (Integer answer)

Correct answer: 7. Dumas method formula: C_xH_y N_z+2x+y/2CuO→xCO_2+y/2H_2O+z/2 N_2+2x+y/2Cu Comparing it with the given compound C_2H_7 N we get y=7

Q26 / 90 · JEE Main 2021 (31 Aug Shift 2) · Chemistry

The transformation occurring in Duma's method is given below
$C_{2} H_{7} N + (2 x + \frac{y}{2}) CuO \to {xCO}_{2} + \frac{y}{2} H_{2} O + \frac{z}{2} N_{2} + (2 x + \frac{y}{2}) Cu$
The value of $y$ is (Integer answer)

Correct answer: 7

Dumas method formula:

$C_{x} H_{y} N_{z} + (2 x + \frac{y}{2}) CuO \to {xCO}_{2} + \frac{y}{2} H_{2} O + \frac{z}{2} N_{2} + (2 x + \frac{y}{2}) Cu$

Comparing it with the given compound $C_{2} H_{7} N$ we get $y = 7$

Hence, the correct answer is 7.