Q152 / 160 · AP EAMCET 2023 (17 May Shift 2) · Physics
The total emf induced in a closely would coil of $\mathrm{N}$ turns in which the magnetic flux linked with the coil changing at the rate $\frac{\mathrm{d} \phi_{\mathrm{B}}}{\mathrm{dt}}$ is
- Correct answerA$-\mathrm{N} \frac{\mathrm{d} \phi_{\mathrm{B}}}{\mathrm{dt}}$
- B$\mathrm{N} \frac{\mathrm{d} \phi_{\mathrm{B}}}{\mathrm{dt}}$
- C$-\mathrm{N} \frac{\mathrm{d}^2 \phi_{\mathrm{B}}}{\mathrm{dt}^2}$
- D$-\frac{\mathrm{d} \phi_{\mathrm{B}}}{\mathrm{dt}}$
Solution
For a coil of $\mathrm{N}$ turns, the emf across the whole coil is $\varepsilon=-\mathrm{N} \frac{\mathrm{d} \phi_{\mathrm{B}}}{\mathrm{dt}}$
Hence, the correct answer is option: 'A'.