An inductor and a resistor of 25 Ω are connected in series to an ac source of voltage 100 sin (100 π t) volt. If the impedance of the circuit is 50 Ω , the average power dissipated per cycle in the circuit is

Q153 / 160 · AP EAMCET 2023 (17 May Shift 2) · Physics

An inductor and a resistor of $25 \Omega$ are connected in series to an ac source of voltage $100 \sin (100 \pi \mathrm{t})$ volt. If the impedance of the circuit is $50 \Omega$, the average power dissipated per cycle in the circuit is

A
$10 \mathrm{~W}$
B
$25 \mathrm{~W}$
C
$50 \mathrm{~W}$
Correct answer
D
$100 \mathrm{~W}$

Solution

The average power dissipated per cycle in the circuit $\mathrm{P}=\frac{\mathrm{V}^2}{\mathrm{Z}^2} \mathrm{R}=\frac{100^2}{50^2} \times 25=100 \mathrm{~W}$

Hence, the correct answer is option: 'D'.

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