Q24 / 160 · AP EAMCET 2014 · Chemistry

The temperature of $K$ at which $\Delta G=0$, for a given reaction with $\Delta H=-20.5 \mathrm{~kJ} \mathrm{~mol}^{-1}$ and $\Delta S=-50.0 \mathrm{JK}^{-1} \mathrm{~mol}^{-1}$ is

  • A
    $-410$
  • Correct answer
    B
    $410$
  • C
    $2.44$
  • D
    $-2.44$

Solution

From Gibbs-Helmholtz reaction, $$ \begin{aligned} \Delta G & =\Delta H-T \Delta S \\ 0 & =-20.5 \times 10^3-T \times(-50.0) \\ \therefore T & =\frac{-20.5 \times 10^3}{-50.0}=410 \mathrm{~K} \end{aligned} $$

Hence, the correct answer is option: 'B'.

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