Q62 / 170 · Manipal (MET) 2018 · Mathematics
The statement $P(n)=9^n-8^n$, when divided 8 , always leaves the remainder
- Correct answerA1
- B2
- C3
- D7
Solution
Given, $P(n)=9^n-8^n$
$\therefore \quad P(1)=9-8=1$
$\therefore \quad P(\mathrm{l})-\mathrm{l}=0$, which is divisible by 8 .
Now, $P(2)=9^2-8^2=17$
When divided by 8 , it leaves the remainder 1 .
Hence, the correct answer is option: 'A'.