Q100 / 170 · Manipal (MET) 2019 · Mathematics
The remainder obtained when $1!+2!+\ldots+200!$ is divided by 14 is
- A$3$
- B$4$
- Correct answerC$5$
- DNone of the above
Solution
$\begin{aligned}
& (1!+2!+3!+4!+5!+\ldots+200!) \div 14 \\
& =1+2+6+24+120+720+(14 M) \\
& =873+14 M=5+868+14 M \\
& =5+14 \times 62+14 M=5+14(62+M)
\end{aligned}$
Hence, when $1!+2!+\ldots+200$ ! is divided by 14 , remainder is 5 .
Hence, when $1!+2!+\ldots+200$ ! is divided by 14 , remainder is 5 .
Hence, the correct answer is option: 'C'.