Q56 / 180 · AIIMS 2008 · Chemistry
The standard oxidation potential \(E^{\circ}\) for the half cell reaction are
\[
\begin{array}{ll}
\mathrm{Zn} \rightarrow \mathrm{Zn}^{2+}+2 e^{-} ; & E^{\circ}=+0.76 \mathrm{~V} \\
\mathrm{Fe} \rightarrow \mathrm{Fe}^{2+}+2 e^{-} ; & E^{\circ}=+0.41 \mathrm{~V}
\end{array}
\]
\(E M F\) of the cell reaction is
\[
\mathrm{Zn}+\mathrm{Fe}^{2+} \rightarrow \mathrm{Zn}^{2+}+\mathrm{Fe}
\]
- A\(-0.35 \mathrm{~V}\)
- Correct answerB\(+0.35 \mathrm{~V}\)
- C\(0.17 \mathrm{~V}\)
- D\(1.17 \mathrm{~V}\).
Solution
$E_{\text {cell }}^{\circ}=0.76-0.41=0.35 \mathrm{~V}$
Hence, the correct answer is option: 'B'.