Q55 / 180 · AIIMS 2008 · Chemistry

For the following concentration cell, to be spontaneous \(\mathrm{Pt}\left(\mathrm{H}_2\right) P_1\) atm. \(|\mathrm{HCl}| \mathrm{Pt}\left(\mathrm{H}_2\right) P_2\) atm. Which of the following is correct?

  • A
    \(P_1=P_2\)
  • B
    \(P_1 < P_2\)
  • Correct answer
    C
    \(P_1>P_2\)
  • D
    Can't be predicted

Solution

$\mathrm{Pt}\left(\mathrm{H}_2\right) \mathrm{P}_1$ atm. $|\mathrm{HCl}| \mathrm{Pt}\left(\mathrm{H}_2\right) \mathrm{P}_2$ atm. For spontaneous reaction, $E_{\text {cell }}$ should be positive so $P_1>P_2$ $E_{\text {cell }}=\frac{0.059}{2} \log \frac{P_1}{P_2}$ Also, if $P_1>P_2$ oxidation occurs at L.H.S. electrode and reduction occurs at R.H.S. electrode.

Hence, the correct answer is option: 'C'.

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