Q27 / 56 · NEST (NISER) 2011 · Chemistry
The standard equilibrium constant $K_P^{\circ}$ is positive and follows the relation
$K_P^{\circ}=\mathrm{e}^{-\Delta G^{\circ} / R T}$
Choose the correct statement(s).
$K_P^{\circ}=\mathrm{e}^{-\Delta G^{\circ} / R T}$
Choose the correct statement(s).
- Correct answerA$\frac{d\left(\ln K_p^{\circ}\right)}{d T}=\frac{\Delta H^{\circ}}{R T^2}$ and the sign of $\Delta H^{\circ}$ determines whether $K_P^{\circ}$ increases or decreases as T increases.
- BOnly the sign of $\Delta S^{\circ}$ determines the temperature dependence of $K_P^{\circ}$.
- Correct answerCAt low $T$, equilibrium position is determined by internal energy change ( $\Delta U^{\circ}$ ).
- Correct answerDAt high $T$, equilibrium position is determined by the entropy change ( $\left.\Delta S^{\circ}\right)$.
Hence, the correct answer is options: 'A', 'C', 'D'.