The spin-only magnetic moment value of the compound with strongest oxidizing ability among ${\mathrm{MnF}}_4,{\mathrm{MnF}}_3$ and ${\mathrm{MnF}}_2$ is_____ $\mathrm{B}.\mathrm{M}$ (nearest integer)

The change from Mn³⁺ to Mn²⁺ results in the half-filled (d⁵ ) configuration which has extra stability.So, MnF₃ has most oxidising tendency.

Hence, ${\mathrm{MnF}}_3$ has the strongest oxidizing ability as it undergoes reduction readily.

Spin only magnetic moment is calculated using the following formula

$\mathrm{\mu }=\sqrt{\mathrm{n}\left(\mathrm{n}+2\right)}\mathrm{B}.\mathrm{M}$

$\mathrm{\mu }=\sqrt{4\left(4+2\right)}=\sqrt{24}=4.89=5 \mathrm{B}.\mathrm{M}$