Q4 / 57 · JEE Advanced 2009 (Paper 2) · Chemistry

The spin only magnetic moment value (in Bohr magneton units) of \mathrm{Cr}(\mathrm{CO})_6$ is

  • Correct answer
    A
    0
  • B
    $2.84$
  • C
    $4.90$
  • D
    $5.92$

Solution

$\mathrm{CO}$ is a strong ligand, all the six electron of the valence shell of $\mathrm{Cr}$ is paired and spin only magnetic moment $=0$.

Hence, the correct answer is option: 'A'.

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