Q21 / 102 · NTA Abhyas (JEE Main) 2020 · Chemistry · Ionic Equilibrium

The solubility of a sparingly soluble salt AOH2 (mol. wt. 192.3) is 19.23  g/litre at 300 K. The pH of its saturated solution assuming 80% ionisation at 300 K is :

  • A
    1.0970
  • B
    12.9030
  • Correct answer
    C
    13.2041
  • D
    12.0000

Solution

S = 19.23 192.3 mol/litre = 0.1 M
A OH 2 ⇌ A 2 + + 2 OH - 2 S
∴   OH - = 0.1 × 2 × 8 0 1 0 0 = 0.16
∴   pOH = 0.7958
∴   pH = 13.2041

Hence, the correct answer is option: 'C'.

More Ionic Equilibrium Questions