Q10 / 82 · NTA Abhyas (JEE Main) 2020 · Mathematics · Quadratic Equation

The smallest possible natural number n, for which the equation x2-nx+2014=0 has integral roots, is

Correct answer: 91

Solution

In x2-nx+2014=0

α+β=n and αβ=2014

Now,

αβ=2014=1×2014 or -1×-2014

=2×1007 or -2×-1007

=19×106 or -19×-106

=38×53 or -38×-53

For least possible value, n=α+β

=38+53

=91

Hence, the correct answer is 91.

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