Q18 / 120 · JEE Advanced 2006 · Chemistry

The smallest ketone and its next homologoue are reacted with $\mathrm{NH}_2 \mathrm{OH}$ to form oxime

  • A
    two different oximes are formed
  • Correct answer
    B
    three different oximes are formed
  • C
    two oximes are optically active
  • D
    all oximes are optically active

Solution

Lowest ketone is $\mathrm{CH}_3 \mathrm{COCH}_3$ (which form an oxime) and its next homologue is $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{COCH}_3$ which form oxime with $\mathrm{NH}_2 \mathrm{OH}$. Such oxime shows the property of geometrical isomerism, i.e., it shows two isomers, symmetric and antisymmertic. (These are differ w.r.t. arrangement towards the space of $-\mathrm{C}=\mathrm{N}$, their different behaviour, can be confirmed with the help of Beckmann's rearrangement. Figure
Figure

Hence, the correct answer is option: 'B'.

More Amines Questions