Q202 / 270 · NDA 2018 (Phase 2) · Mathematics
The second degree equation $x^2+4 y-2 x-4 y+2=0$ represents
- Correct answerAA point
- BAn ellipse of semi-major axis 1
- CAn ellipse with eccentricity $\frac{\sqrt{3}}{2}$
- DNone of the above
Solution
$\begin{array}{ll}
\because & \left(x^2-2 x+1\right)+\left(4 y^2-4 y+1\right)=0 \\
\Rightarrow & (x-1)^2+(2 y-1)^2=0 \\
\Rightarrow & x=1, y=\frac{1}{2}
\end{array}$
It is a point.
Hence, the correct answer is option: 'A'.