Q201 / 270 · NDA 2018 (Phase 2) · Mathematics

The equation of a circle whose end points of a diameter are $\left(\mathrm{x}_1, \mathrm{y}_1\right)$ and $\left(\mathrm{x}_2, \mathrm{y}_2\right)$ is

  • A
    $\left(x-x_1\right)\left(x-x_2\right)+\left(y-y_1\right)\left(y-y_2\right)=x^2+y^2$
  • B
    $\left(x-x_1\right)^2+\left(y-y_1\right)^2=x_2 y_2$
  • C
    $x^2+y^2+2 x_1 x_2+2 y_1 y_2=0$
  • Correct answer
    D
    $\left(x-x_1\right)\left(x-x_2\right)+\left(y-y_1\right)\left(y-y_2\right)=0$

Solution

Equation of circle is $\left(x-x_1\right)\left(x-x_2\right)+\left(y-y_1\right)\left(y-y_2\right)=0$

Hence, the correct answer is option: 'D'.

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