Q42 / 180 · KCET 2009 · Chemistry

The rms velocity of molecules of a gas of density $4 \mathrm{~kg} \mathrm{~m}^{-3}$ and pressure $1.2 \times 10^{5} \mathrm{Nm}^{-2}$ is

  • Correct answer
    A
    $300 \mathrm{~ms}^{-1}$
  • B
    $900 \mathrm{~ms}^{-1}$
  • C
    $120 \mathrm{~ms}^{-1}$
  • D
    $600 \mathrm{~ms}^{-1}$

Solution

$\begin{aligned} \mathrm{v}_{\mathrm{rms}} &=\sqrt{\frac{3 \mathrm{p}}{\mathrm{d}}} \\ &=\sqrt{\frac{3 \times 1.2 \times 10^{5}}{4}}=300 \mathrm{~ms}^{-1} \end{aligned}$

Hence, the correct answer is option: 'A'.

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