Q107 / 150 · MHT CET 2021 (21 Sep Shift 1) · Physics
The resultant capacity between points $\mathrm{A}$ and $\mathrm{B}$ in the given circuit is




- A$\mathrm{C}$
- B$\frac{\mathrm{C}}{3}$
- Correct answerC$3 \mathrm{C}$
- D$2 \mathrm{C}$
Solution

$\mathrm{C}_1$ and $\mathrm{C}_2$ are in parallel, their equivalent capacitance $\mathrm{C}_7=2 \mathrm{C}$ $\mathrm{C}_7$ and $\mathrm{C}_3$ are in series, their equivalent capacitance is $\mathrm{C}_8=\mathrm{C}$ $\mathrm{C}_8$ and $\mathrm{C}_4$ are in parallel, their equivalent capacitance is $\mathrm{C}_9=2 \mathrm{C}$ $\mathrm{C}_9$ and $\mathrm{C}_5$ are in series, their equivalent capacitance $\mathrm{C}_{10}=\mathrm{C}$ $\mathrm{C}_{10}$ and $\mathrm{C}_6$ are in parallel, their equivalent capacitance is $3 \mathrm{C}$ Hence equivalent capacitance between $\mathrm{A}$ and $\mathrm{B}$ is $3 \mathrm{C}$
Hence, the correct answer is option: 'C'.