Q131 / 150 · MHT CET 2026 (18 April Shift 2) · Physics
Three identical capacitors connected in series have net capacitance '$x$'. Then they are connected in parallel. The ratio of energy stored in series configuration to that in parallel configuration is (if both configurations are connected to the same source)
- A$1:3$
- B$3:1$
- Correct answerC$1:9$
- D$9:1$
Solution
Let the capacitance of each identical capacitor be $C$.
In series configuration, the equivalent capacitance is $C_s = \dfrac{C}{3}$.
In parallel configuration, the equivalent capacitance is $C_p = 3C$.
The energy stored in a capacitor configuration connected to a voltage source $V$ is given by $U = \dfrac{1}{2} C_{eq} V^2$.
For the series configuration, the energy stored is $U_s = \dfrac{1}{2} C_s V^2 = \dfrac{1}{2} \left(\dfrac{C}{3}\right) V^2$.
For the parallel configuration, the energy stored is $U_p = \dfrac{1}{2} C_p V^2 = \dfrac{1}{2} (3C) V^2$.
The ratio of energy stored in series to that in parallel is:
$\dfrac{U_s}{U_p} = \dfrac{\dfrac{1}{2} \left(\dfrac{C}{3}\right) V^2}{\dfrac{1}{2} (3C) V^2} = \dfrac{\dfrac{C}{3}}{3C} = \dfrac{1}{9}$
Thus, the required ratio is $1:9$.
Answer: $1:9$
In series configuration, the equivalent capacitance is $C_s = \dfrac{C}{3}$.
In parallel configuration, the equivalent capacitance is $C_p = 3C$.
The energy stored in a capacitor configuration connected to a voltage source $V$ is given by $U = \dfrac{1}{2} C_{eq} V^2$.
For the series configuration, the energy stored is $U_s = \dfrac{1}{2} C_s V^2 = \dfrac{1}{2} \left(\dfrac{C}{3}\right) V^2$.
For the parallel configuration, the energy stored is $U_p = \dfrac{1}{2} C_p V^2 = \dfrac{1}{2} (3C) V^2$.
The ratio of energy stored in series to that in parallel is:
$\dfrac{U_s}{U_p} = \dfrac{\dfrac{1}{2} \left(\dfrac{C}{3}\right) V^2}{\dfrac{1}{2} (3C) V^2} = \dfrac{\dfrac{C}{3}}{3C} = \dfrac{1}{9}$
Thus, the required ratio is $1:9$.
Answer: $1:9$
Hence, the correct answer is option: 'C'.