Q131 / 150 · MHT CET 2026 (18 April Shift 2) · Physics

Three identical capacitors connected in series have net capacitance '$x$'. Then they are connected in parallel. The ratio of energy stored in series configuration to that in parallel configuration is (if both configurations are connected to the same source)

  • A
    $1:3$
  • B
    $3:1$
  • Correct answer
    C
    $1:9$
  • D
    $9:1$

Solution

Let the capacitance of each identical capacitor be $C$.

In series configuration, the equivalent capacitance is $C_s = \dfrac{C}{3}$.

In parallel configuration, the equivalent capacitance is $C_p = 3C$.

The energy stored in a capacitor configuration connected to a voltage source $V$ is given by $U = \dfrac{1}{2} C_{eq} V^2$.

For the series configuration, the energy stored is $U_s = \dfrac{1}{2} C_s V^2 = \dfrac{1}{2} \left(\dfrac{C}{3}\right) V^2$.

For the parallel configuration, the energy stored is $U_p = \dfrac{1}{2} C_p V^2 = \dfrac{1}{2} (3C) V^2$.

The ratio of energy stored in series to that in parallel is:

$\dfrac{U_s}{U_p} = \dfrac{\dfrac{1}{2} \left(\dfrac{C}{3}\right) V^2}{\dfrac{1}{2} (3C) V^2} = \dfrac{\dfrac{C}{3}}{3C} = \dfrac{1}{9}$

Thus, the required ratio is $1:9$.

Answer: $1:9$

Hence, the correct answer is option: 'C'.

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