The resistivity of a 0.8M solution of an electrolyte is 5×10^(-3)Ωcm. Its molar conductivity is 10^4Ω^(-1) cm^2 mol^(-1). (Nearest integer)

Q29 / 90 · JEE Main 2023 (31 Jan Shift 2) · Chemistry

The resistivity of a $0.8 M$ solution of an electrolyte is $5 \times 10^{- 3} Ωcm$ . Its molar conductivity is $10^{4} Ω^{- 1} {cm}^{2} {mol}^{- 1}$ . (Nearest integer)

Correct answer: 25

Given,
Resistivity $(ρ) = 5 \times 10^{- 3} Ωcm$

Molarity $(M) = 0.8 M$

Thus, Molar conductivity of electrolyte $(λ_{M}) = \frac{1}{ρ} \times \frac{1000}{M}$

$= \frac{1}{5 \times 10^{- 3}} \times \frac{1000}{0.8}$

$= 0.25 \times 10^{6}$

$= 25 \times 10^{4} {cm}^{2} {mol}^{- 1}$ .

Hence, the correct answer is 25.