The real force ‘ $F$ ’ acting on a particle of mass ‘ $m$ ’ performing circular motion acts along the radius of circle ‘ $r$ ’ and is directed towards the centre of circle. The square root of magnitude of such force is $\left(T=\mathrm{p}\mathrm{e}\mathrm{r}\mathrm{i}\mathrm{o}\mathrm{d}\mathrm{i}\mathrm{c}\mathrm{}\mathrm{t}\mathrm{i}\mathrm{m}\mathrm{e}\right)$

• Correct answer
  A

  $\frac{2\pi }{T}\sqrt{mr}$
• B

  $\frac{Tmr}{4\pi }$
• C

  $\frac{2\pi T}{\sqrt{mr}}$
• D

  $\frac{T^{2}mr}{4\pi }$

Hence, the correct answer is option: 'A'.