Q112 / 150 · MHT CET 2026 (19 April Shift 2) · Physics
A particle is performing U.C.M. along a circle of radius $R$. In half the period of revolution, its displacement and distance covered are respectively
- A$\sqrt{2}R, 2\pi R$
- Correct answerB$2R, \pi R$
- C$2R, 2\pi R$
- D$R, \pi R$
Solution
In half the period of revolution, the particle moves from its initial position to the diametrically opposite point on the circular path.
The displacement is the shortest distance between the initial and final positions, which is equal to the diameter of the circle.
Displacement = $2R$
The distance covered is the actual path length along the circular trajectory, which is half of the circumference.
Distance = $\dfrac{2\pi R}{2} = \pi R$
Answer: $2R, \pi R$
The displacement is the shortest distance between the initial and final positions, which is equal to the diameter of the circle.
Displacement = $2R$
The distance covered is the actual path length along the circular trajectory, which is half of the circumference.
Distance = $\dfrac{2\pi R}{2} = \pi R$
Answer: $2R, \pi R$
Hence, the correct answer is option: 'B'.